Python字典实现伪切片功能
(编辑：jimmy 日期: 2024/11/17 浏览：3 次 )
故事是从这里开始的…
早上起床看到一条评论,有点懵逼,字典切片"htmlcode">
# 字典切片1.0版本
def dictcut(dict, start, end):
# 临时存放字典的key
temp = list(dict.keys())
# 返回一个字典
result = {}
#切列表里的key
temp = temp[start:end]
for i in range(len(temp)):
#用切完后的key列表对新的字典赋值
result[temp[i]] = dict.get(temp[i])
return result
#原字典
dict = {"zero": "0", "one": "1", "two": "2", "three": "3", "four": "4"}
print("dict:", dict)
start = eval(input("起始位置:"))
end = eval(input("结束位置:"))
#调用切片方法
newdict =dictcut(dict, start, end)
print("dictcut(dict,%d,%d):" % (start, end), newdict)
然后运行结果
两个数为正,而且不越界,正常截取
如果我想从2截取到末尾,末尾坐标是-1,但传[2 : -1]就会截取[2,-1),截取不到最后一个;那如果传[2 : 0]就会像下面一样
所以list[2: ]截取从2到最后一个,在传参方面就显得很麻烦了
如果截取[-5,-3]没问题,但是[-3,-5]就不行了
综上,我希望我的字典切片可以三百六四度无死角切,从正到负,从前到后,正着切,逆着切
所以字典切片2.0版本就登场了!
# 字典切片2.0
def dictcut(dict, start, end):
# 临时存放字典的key
temp = list(dict.keys())
# 返回一个字典
result = {}
# 分两个分支 1.start和end在可切片范围内 2.不在范围内
if start <= len(temp) - 1 and start >= -len(temp) and end <= len(temp) - 1 and end >= -len(temp):
#start大于end,且下标不重叠
if start > end and start - 1 != len(temp) + end:
#start和end同时为大于等于0
if start >= 0 and end >= 0:
# (4,2) 4 0 1
for i in range(start, len(temp)):
result[temp[i]] = dict.get(temp[i])
for i in range(0, end):
result[temp[i]] = dict.get(temp[i])
# start和end同时小等于0
if start <= 0 and end <= 0:
# (-1,-3) 4 0 1
for i in range(len(temp) + start, len(temp)):
result[temp[i]] = dict.get(temp[i])
for i in range(0, len(temp) + end):
result[temp[i]] = dict.get(temp[i])
# start大于0,end小于0
if start >= 0 and end < 0:
# (1,-2) 1 2
for i in range(start, len(temp) + end):
result[temp[i]] = dict.get(temp[i])
# end大于start,且下标不重叠
elif end > start and start + len(temp) != end - 1:
# start和end同时为大于等于0
if start >= 0 and end >= 0:
# (0,3) 0 1 2
for i in range(start, end):
result[temp[i]] = dict.get(temp[i])
# start和end同时大小等于0
if start <= 0 and end <= 0:
# (-4,-1) 1 2 3
for i in range(len(temp) + start, len(temp) + end):
result[temp[i]] = dict.get(temp[i])
# end大等于0,start小于0
if end >= 0 and start < 0:
# (-1,3) 4 0 1 2
for i in range(len(temp) + start, len(temp)):
result[temp[i]] = dict.get(temp[i])
for i in range(end):
result[temp[i]] = dict.get(temp[i])
#start等于end,或者下标重叠
elif end == start or start + len(temp) == end - 1 or end <= 0 and start - 1 == len(temp) + end:
print("切了个寂寞！")
# start或者end不在范围内
else:
print("传入参数有误！")
return result
#原字典
dict = {"zero": "0", "one": "1", "two": "2", "three": "3", "four": "4"}
print("dict:", dict)
print("字典切割:左闭右开")
start = eval(input("起始位置:"))
end = eval(input("结束位置:"))
newdict = dictcut(dict, start, end)
# 如果返回的字典不为空，打印结果
if len(newdict) != 0:
print("dictcut(dict,%d,%d):" % (start, end), newdict)
运行结果:
若不在范围
如果坐标重叠,重叠切个寂寞哦"text-align: center">
360°无死角切切切(正常切)
正数
负数
360°无死角切切切(从后往前切)
正数
负数
2.0代码比较繁琐,但是字典切片的效果还是清晰可见的~~~
下一篇：python实现一个简单RPC框架的示例