python爬虫开发之使用Python爬虫库requests多线程抓取猫眼电影TOP100实例

(编辑：jimmy 日期: 2024/11/19 浏览：3 次 )

使用Python爬虫库requests多线程抓取猫眼电影TOP100思路：

查看网页源代码
抓取单页内容
正则表达式提取信息
猫眼TOP100所有信息写入文件
多线程抓取

运行平台：windows
Python版本：Python 3.7.
IDE:Sublime Text
浏览器：Chrome浏览器

1.查看猫眼电影TOP100网页原代码

按F12查看网页源代码发现每一个电影的信息都在“<dd></dd>”标签之中。

点开之后，信息如下：

2.抓取单页内容

在浏览器中打开猫眼电影网站，点击“榜单”，再点击“TOP100榜”如下图：

接下来通过以下代码获取网页源代码：

#-*-coding:utf-8-*-
import requests
from requests.exceptions import RequestException
 
#猫眼电影网站有反爬虫措施，设置headers后可以爬取
headers = {
	'Content-Type': 'text/plain; charset=UTF-8',
	'Origin':'https://maoyan.com',
	'Referer':'https://maoyan.com/board/4',
	'User-Agent':'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/67.0.3396.99 Safari/537.36'
	}
 
#爬取网页源代码
def get_one_page(url,headers):
	try:
		response =requests.get(url,headers =headers)
		if response.status_code == 200:
			return response.text
		return None
	except RequestsException:
		return None
 
def main():
	url = "https://maoyan.com/board/4"
	html = get_one_page(url,headers)
	print(html)
 
if __name__ == '__main__':
	main()

执行结果如下：

3.正则表达式提取信息

上图标示信息即为要提取的信息，代码实现如下：

#-*-coding:utf-8-*-
import requests
import re
from requests.exceptions import RequestException
 
#猫眼电影网站有反爬虫措施，设置headers后可以爬取
headers = {
	'Content-Type': 'text/plain; charset=UTF-8',
	'Origin':'https://maoyan.com',
	'Referer':'https://maoyan.com/board/4',
	'User-Agent':'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/67.0.3396.99 Safari/537.36'
	}
 
#爬取网页源代码
def get_one_page(url,headers):
	try:
		response =requests.get(url,headers =headers)
		if response.status_code == 200:
			return response.text
		return None
	except RequestsException:
		return None
 
#正则表达式提取信息
def parse_one_page(html):
	pattern = re.compile('<dd>.*"(.*".*"><a'
		+'.*?>(.*">(.*">(.*">(.*">(.*"https://maoyan.com/board/4"
	html = get_one_page(url,headers)
	for item in parse_one_page(html):
		print(item)
 
if __name__ == '__main__':
	main()

执行结果如下：

4.猫眼TOP100所有信息写入文件

上边代码实现单页的信息抓取，要想爬取100个电影的信息，先观察每一页url的变化，点开每一页我们会发现url进行变化，原url后面多了‘？offset=0',且offset的值变化从0,10,20，变化如下：

代码实现如下：

#-*-coding:utf-8-*-
import requests
import re
import json
import os
from requests.exceptions import RequestException
 
#猫眼电影网站有反爬虫措施，设置headers后可以爬取
headers = {
	'Content-Type': 'text/plain; charset=UTF-8',
	'Origin':'https://maoyan.com',
	'Referer':'https://maoyan.com/board/4',
	'User-Agent':'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/67.0.3396.99 Safari/537.36'
	}
 
#爬取网页源代码
def get_one_page(url,headers):
	try:
		response =requests.get(url,headers =headers)
		if response.status_code == 200:
			return response.text
		return None
	except RequestsException:
		return None
 
#正则表达式提取信息
def parse_one_page(html):
	pattern = re.compile('<dd>.*"(.*".*"><a'
		+'.*?>(.*">(.*">(.*">(.*">(.*"https://maoyan.com/board/4"+str(offset)
	html = get_one_page(url,headers)
	if not os.path.exists('covers'):
		os.mkdir('covers')	
	for item in parse_one_page(html):
		print(item)
		write_to_file(item)
		save_image_file(item['image'],'covers/'+item['title']+'.jpg')
 
if __name__ == '__main__':
	#对每一页信息进行爬取
	for i in range(10):
		main(i*10)

爬取结果如下：

5.多线程抓取

进行比较，发现多线程爬取时间明显较快：

多线程：

以下为完整代码：

#-*-coding:utf-8-*-
import requests
import re
import json
import os
from requests.exceptions import RequestException
from multiprocessing import Pool
#猫眼电影网站有反爬虫措施，设置headers后可以爬取
headers = {
	'Content-Type': 'text/plain; charset=UTF-8',
	'Origin':'https://maoyan.com',
	'Referer':'https://maoyan.com/board/4',
	'User-Agent':'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/67.0.3396.99 Safari/537.36'
	}
 
#爬取网页源代码
def get_one_page(url,headers):
	try:
		response =requests.get(url,headers =headers)
		if response.status_code == 200:
			return response.text
		return None
	except RequestsException:
		return None
 
#正则表达式提取信息
def parse_one_page(html):
	pattern = re.compile('<dd>.*"(.*".*"><a'
		+'.*?>(.*">(.*">(.*">(.*">(.*"https://maoyan.com/board/4"+str(offset)
	html = get_one_page(url,headers)
	if not os.path.exists('covers'):
		os.mkdir('covers')	
	for item in parse_one_page(html):
		print(item)
		write_to_file(item)
		save_image_file(item['image'],'covers/'+item['title']+'.jpg')
 
if __name__ == '__main__':
	#对每一页信息进行爬取
	pool = Pool()
	pool.map(main,[i*10 for i in range(10)])
	pool.close()
	pool.join()

本文主要讲解了使用Python爬虫库requests多线程抓取猫眼电影TOP100数据的实例,更多关于Python爬虫库的知识请查看下面的相关链接

上一篇：python 获取当前目录下的文件目录和文件名实例代码详解
下一篇：Django 404、500页面全局配置知识点详解