Python3查找列表中重复元素的个数的3种方法详解
(编辑：jimmy 日期: 2024/11/19 浏览：3 次 )
方法一：
mylist = [1,2,2,2,2,3,3,3,4,4,4,4]
myset = set(mylist)
for item in myset:
print("the %d has found %d" %(item,mylist.count(item)))
the 1 has found 1
the 2 has found 4
the 3 has found 3
the 4 has found 4
方法二：
from collections import Counter
Counter([1,2,2,2,2,3,3,3,4,4,4,4])
Counter({2: 4, 4: 4, 3: 3, 1: 1})
方法三：
List=[1,2,2,2,2,3,3,3,4,4,4,4]
a = {}
for i in List:
if List.count(i)>1:
a[i] = List.count(i)
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