python批量处理文件或文件夹
(编辑:jimmy 日期: 2024/11/21 浏览:3 次 )
本文实例为大家分享了python批量处理文件或文件夹的具体代码,供大家参考,具体内容如下
# -*- coding: utf-8 -*- import os,shutil import sys import numpy as np ##########批量删除不同文件夹下的同名文件夹############# def arrange_file(dir_path0): for dirpath,dirnames,filenames in os.walk(dir_path0): if 'my_result' in dirpath: # print(dirpath) shutil.rmtree(dirpath) ##########批量在不同文件夹下新建同名子文件夹并把文件搬移到子文件夹############# def arrange_file(dir_path0): for dirpath,dirnames,filenames in os.walk(dir_path0): for files in filenames: total_path = os.path.join(dirpath,files) root_path,file_path = total_path.split(dir_path,1) if 'png' in file_path: new_file_path = '.' + file_path[:-9] + 'new_file_name/' # print(file_path) # print(new_file_path) # print(new_file_path + file_path[-9:]) # if not os.path.exists(new_file_path): # os.makedirs(new_file_path) # shutil.move('.' + file_path,new_file_path + file_path[-9:]) ##########批量删除不同文件夹下符合条件的文件################## def arrange_file(dir_path0): for dirpath,dirnames,filenames in os.walk(dir_path0): for files in filenames: total_path = os.path.join(dirpath,files) # print(total_path) if 'jpg' in total_path and 'labels' in total_path: img = cv2.imread(total_path) if np.sum(img) == 0: print(total_path) os.remove(total_path) ###########批量把文件搬移到上一层文件夹并删除当前文件夹######## def arrange_file(dir_path0): for dirpath,dirnames,filenames in os.walk(dir_path0): for files in filenames: total_path = os.path.join(dirpath,files) root_path,file_path = total_path.split(dir_path0,1) # print(file_path[:-48]) # return 0 if 'jpg' in file_path: new_file_path = dir_path0 + file_path[:-48] shutil.move(dir_path0 + file_path,new_file_path + file_path[-9:]) for dirpath,dirnames,filenames in os.walk(dir_path0): file_path = dirpath.split('./your_total_path')[1] if 'keywords' in file_path: # print(dirpath) shutil.rmtree(dirpath) if __name__=='__main__': dir_path0 = './your_total_path' arrange_file(dir_path0)
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