python实现DES加密解密方法实例详解
(编辑:jimmy 日期: 2024/11/18 浏览:3 次 )
本文实例讲述了python实现DES加密解密方法。分享给大家供大家参考。具体分析如下:
实现功能:加密中文等字符串
密钥与明文可以不等长
这里只贴代码,加密过程可以自己百度,此处python代码没有优化
1. desstruct.py DES加密中要使用的结构体
ip= (58, 50, 42, 34, 26, 18, 10, 2, 60, 52, 44, 36, 28, 20, 12, 4, 62, 54, 46, 38, 30, 22, 14, 6, 64, 56, 48, 40, 32, 24, 16, 8, 57, 49, 41, 33, 25, 17, 9 , 1, 59, 51, 43, 35, 27, 19, 11, 3, 61, 53, 45, 37, 29, 21, 13, 5, 63, 55, 47, 39, 31, 23, 15, 7) ip_1=(40, 8, 48, 16, 56, 24, 64, 32, 39, 7, 47, 15, 55, 23, 63, 31, 38, 6, 46, 14, 54, 22, 62, 30, 37, 5, 45, 13, 53, 21, 61, 29, 36, 4, 44, 12, 52, 20, 60, 28, 35, 3, 43, 11, 51, 19, 59, 27, 34, 2, 42, 10, 50, 18, 58, 26, 33, 1, 41, 9, 49, 17, 57, 25) e =(32, 1, 2, 3, 4, 5, 4, 5, 6, 7, 8, 9, 8, 9, 10, 11, 12,13, 12, 13, 14, 15, 16, 17, 16,17, 18, 19, 20, 21, 20, 21, 22, 23, 24, 25,24, 25, 26, 27, 28, 29,28, 29, 30, 31, 32, 1) p=(16, 7, 20, 21, 29, 12, 28, 17, 1, 15, 23, 26, 5, 18, 31, 10, 2, 8, 24, 14, 32, 27, 3, 9, 19, 13, 30, 6, 22, 11, 4, 25) s=[ [[14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7], [0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8], [4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0], [15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13]], [[15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10], [3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5], [0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15], [13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9]], [[10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8], [13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1], [13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7], [1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12]], [[7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15], [13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14,9], [10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4], [3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14]], [[2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9], [14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6], [4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14], [11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3]], [[12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11], [10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8], [9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6], [4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13]], [[4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1], [13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6], [1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2], [6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12]], [[13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7], [1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2], [7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8], [2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11]]] pc1=(57, 49, 41, 33, 25, 17, 9, 1, 58, 50, 42, 34, 26, 18, 10, 2, 59, 51, 43, 35, 27, 19, 11, 3, 60, 52, 44, 36, 63, 55, 47, 39, 31, 33, 15, 7, 62, 54, 46, 38, 30, 22, 14, 6, 61, 53, 45, 37, 29, 21, 13, 5, 28, 20, 12, 4); pc2= (14, 17, 11, 24, 1, 5, 3, 28, 15, 6, 21, 10, 23, 19, 12, 4, 26, 8, 16, 7, 27, 20, 13, 2, 41, 52, 31, 37, 47, 55, 30, 40, 51, 45, 33, 48, 44, 49, 39, 56, 34, 53, 46, 42, 50, 36, 29, 32) d = ( 1, 1, 2, 2, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 2, 1)
2. des.py 加密文件
#_*_ coding:utf-8 _*_ #!/usr/bin/env python #Filename:des.py from desstruct import * import re __all__=['desencode'] class DES(): '''des 加密''' def __init__(self): pass #加密 def code(self,from_code,key,code_len,key_len): output="" trun_len=0 #将密文和密钥转换为二进制 code_string=self._functionCharToA(from_code,code_len) code_key=self._functionCharToA(key,key_len) #如果密钥长度不是16的整数倍则以增加0的方式变为16的整数倍 if code_len%16!=0: real_len=(code_len/16)*16+16 else: real_len=code_len if key_len%16!=0: key_len=(key_len/16)*16+16 key_len*=4 #每个16进制占4位 trun_len=4*real_len #对每64位进行一次加密 for i in range(0,trun_len,64): run_code=code_string[i:i+64] l=i%key_len run_key=code_key[l:l+64] #64位明文、密钥初始置换 run_code= self._codefirstchange(run_code) run_key= self._keyfirstchange(run_key) #16次迭代 for j in range(16): #取出明文左右32位 code_r=run_code[32:64] code_l=run_code[0:32] #64左右交换 run_code=code_r #右边32位扩展置换 code_r= self._functionE(code_r) #获取本轮子密钥 key_l=run_key[0:28] key_r=run_key[28:56] key_l=key_l[d[j]:28]+key_l[0:d[j]] key_r=key_r[d[j]:28]+key_r[0:d[j]] run_key=key_l+key_r key_y= self._functionKeySecondChange(run_key) #异或 code_r= self._codeyihuo(code_r,key_y) #S盒代替/选择 code_r= self._functionS(code_r) #P转换 code_r= self._functionP(code_r) #异或 code_r= self._codeyihuo(code_l,code_r) run_code+=code_r #32互换 code_r=run_code[32:64] code_l=run_code[0:32] run_code=code_r+code_l #将二进制转换为16进制、逆初始置换 output+=self._functionCodeChange(run_code) return output #异或 def _codeyihuo(self,code,key): code_len=len(key) return_list='' for i in range(code_len): if code[i]==key[i]: return_list+='0' else: return_list+='1' return return_list #密文或明文初始置换 def _codefirstchange(self,code): changed_code='' for i in range(64): changed_code+=code[ip[i]-1] return changed_code #密钥初始置换 def _keyfirstchange (self,key): changed_key='' for i in range(56): changed_key+=key[pc1[i]-1] return changed_key #逆初始置换 def _functionCodeChange(self, code): lens=len(code)/4 return_list='' for i in range(lens): list='' for j in range(4): list+=code[ip_1[i*4+j]-1] return_list+="%x" %int(list,2) return return_list #扩展置换 def _functionE(self,code): return_list='' for i in range(48): return_list+=code[e[i]-1] return return_list #置换P def _functionP(self,code): return_list='' for i in range(32): return_list+=code[p[i]-1] return return_list #S盒代替选择置换 def _functionS(self, key): return_list='' for i in range(8): row=int( str(key[i*6])+str(key[i*6+5]),2) raw=int(str( key[i*6+1])+str(key[i*6+2])+str(key[i*6+3])+str(key[i*6+4]),2) return_list+=self._functionTos(s[i][row][raw],4) return return_list #密钥置换选择2 def _functionKeySecondChange(self,key): return_list='' for i in range(48): return_list+=key[pc2[i]-1] return return_list #将十六进制转换为二进制字符串 def _functionCharToA(self,code,lens): return_code='' lens=lens%16 for key in code: code_ord=int(key,16) return_code+=self._functionTos(code_ord,4) if lens!=0: return_code+='0'*(16-lens)*4 return return_code #二进制转换 def _functionTos(self,o,lens): return_code='' for i in range(lens): return_code=str(oi &1)+return_code return return_code #将unicode字符转换为16进制 def tohex(string): return_string='' for i in string: return_string+="%02x"%ord(i) return return_string def tounicode(string): return_string='' string_len=len(string) for i in range(0,string_len,2): return_string+=chr(int(string[i:i+2],16)) return return_string #入口函数 def desencode(from_code,key): #转换为16进制 from_code=tohex(from_code) key=tohex(key) des=DES() key_len=len(key) string_len=len(from_code) if string_len<1 or key_len<1: print 'error input' return False key_code= des.code(from_code,key,string_len,key_len) return key_code #测试 if __name__ == '__main__': print desencode('我是12345678刘就是我abcdwfd','0f1571c947刘') #返回密文为: 84148584371a6a1fe99e1da0ce1e34649b88ed15098e8aa4b8eb0bf24885c658
3. 解密文件
#_*_coding:utf-8_*_ #!/usr/bin/env python #Filename:des.py from desstruct import * import re __all__=['desdecode'] class DES(): '''解密函数,DES加密与解密的方法相差不大 只是在解密的时候所用的子密钥与加密的子密钥相反 ''' def __init__(self): pass def decode(self,string,key,key_len,string_len): output="" trun_len=0 num=0 #将密文转换为二进制 code_string=self._functionCharToA(string,string_len) #获取字密钥 code_key=self._getkey(key,key_len) #如果密钥长度不是16的整数倍则以增加0的方式变为16的整数倍 real_len=(key_len/16)+1 if key_len%16!=0 else key_len/16 trun_len=string_len*4 #对每64位进行一次加密 for i in range(0,trun_len,64): run_code=code_string[i:i+64] run_key=code_key[num%real_len] #64位明文初始置换 run_code= self._codefirstchange(run_code) #16次迭代 for j in range(16): code_r=run_code[32:64] code_l=run_code[0:32] #64左右交换 run_code=code_r #右边32位扩展置换 code_r= self._functionE(code_r) #获取本轮子密钥 key_y=run_key[15-j] #异或 code_r= self._codeyihuo(code_r,key_y) #S盒代替/选择 code_r= self._functionS(code_r) #P转换 code_r= self._functionP(code_r) #异或 code_r= self._codeyihuo(code_l,code_r) run_code+=code_r num+=1 #32互换 code_r=run_code[32:64] code_l=run_code[0:32] run_code=code_r+code_l #将二进制转换为16进制、逆初始置换 output+=self._functionCodeChange(run_code) return output #获取子密钥 def _getkey(self,key,key_len): #将密钥转换为二进制 code_key=self._functionCharToA(key,key_len) a=['']*16 real_len=(key_len/16)*16+16 if key_len%16!=0 else key_len b=['']*(real_len/16) for i in range(real_len/16): b[i]=a[:] num=0 trun_len=4*key_len for i in range(0,trun_len,64): run_key=code_key[i:i+64] run_key= self._keyfirstchange(run_key) for j in range(16): key_l=run_key[0:28] key_r=run_key[28:56] key_l=key_l[d[j]:28]+key_l[0:d[j]] key_r=key_r[d[j]:28]+key_r[0:d[j]] run_key=key_l+key_r key_y= self._functionKeySecondChange(run_key) b[num][j]=key_y[:] num+=1 return b #异或 def _codeyihuo(self,code,key): code_len=len(key) return_list='' for i in range(code_len): if code[i]==key[i]: return_list+='0' else: return_list+='1' return return_list #密文或明文初始置换 def _codefirstchange(self,code): changed_code='' for i in range(64): changed_code+=code[ip[i]-1] return changed_code #密钥初始置换 def _keyfirstchange (self,key): changed_key='' for i in range(56): changed_key+=key[pc1[i]-1] return changed_key #逆初始置换 def _functionCodeChange(self, code): return_list='' for i in range(16): list='' for j in range(4): list+=code[ip_1[i*4+j]-1] return_list+="%x" %int(list,2) return return_list #扩展置换 def _functionE(self,code): return_list='' for i in range(48): return_list+=code[e[i]-1] return return_list #置换P def _functionP(self,code): return_list='' for i in range(32): return_list+=code[p[i]-1] return return_list #S盒代替选择置换 def _functionS(self, key): return_list='' for i in range(8): row=int( str(key[i*6])+str(key[i*6+5]),2) raw=int(str( key[i*6+1])+str(key[i*6+2])+str(key[i*6+3])+str(key[i*6+4]),2) return_list+=self._functionTos(s[i][row][raw],4) return return_list #密钥置换选择2 def _functionKeySecondChange(self,key): return_list='' for i in range(48): return_list+=key[pc2[i]-1] return return_list #将十六进制转换为二进制字符串 def _functionCharToA(self,code,lens): return_code='' lens=lens%16 for key in code: code_ord=int(key,16) return_code+=self._functionTos(code_ord,4) if lens!=0: return_code+='0'*(16-lens)*4 return return_code #二进制转换 def _functionTos(self,o,lens): return_code='' for i in range(lens): return_code=str(oi &1)+return_code return return_code #将unicode字符转换为16进制 def tohex(string): return_string='' for i in string: return_string+="%02x"%ord(i) return return_string def tounicode(string): return_string='' string_len=len(string) for i in range(0,string_len,2): return_string+=chr(int(string[i:i+2],16)) return return_string #入口函数 def desdecode(from_code,key): key=tohex(key) des=DES() key_len=len(key) string_len=len(from_code) if string_len%16!=0: return False if string_len<1 or key_len<1: return False key_code= des.decode(from_code,key,key_len,string_len) return tounicode(key_code) #测试 if __name__ == '__main__': print desdecode('84148584371a6a1fe99e1da0ce1e34649b88ed15098e8aa4b8eb0bf24885c658','0f1571c947刘'
解密后为: 我是12345678刘就是我abcdwfd
Python DES 加密解密,就是大家所谓想要的那个非常快速的方法
这个要借助Crypto.Cipher这个插件来实现的,引用后只需要写如下代码即可
from Crypto.Cipher import DES class MyDESCrypt: key = chr(11)+chr(11)+chr(11)+chr(11)+chr(11)+chr(11)+chr(11)+chr(11) iv = chr(22)+chr(22)+chr(22)+chr(22)+chr(22)+chr(22)+chr(22)+chr(22) def __init__(self,key='',iv=''): if len(key)> 0: self.key = key if len(iv)>0 : self.iv = iv def ecrypt(self,ecryptText): try: cipherX = DES.new(self.key, DES.MODE_CBC, self.iv) pad = 8 - len(ecryptText) % 8 padStr = "" for i in range(pad): padStr = padStr + chr(pad) ecryptText = ecryptText + padStr x = cipherX.encrypt(ecryptText) return x.encode('hex_codec').upper() except: return "" def decrypt(self,decryptText): try: cipherX = DES.new(self.key, DES.MODE_CBC, self.iv) str = decryptText.decode('hex_codec') y = cipherX.decrypt(str) return y[0:ord(y[len(y)-1])*-1] except: return ""
建议大家可以结合一些插件使用,更方便与快捷
希望本文所述对大家的Python程序设计有所帮助。
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